OA = 5,Sina OE = 4/5;
∴AF=4, OF=3, which is a (-3,4).
And ∵A versus inverse proportional function y=m/x,
∴, 4=m/(-3), that is, m=- 12, then the inverse proportional function y =-12/x.
②∫B(6, n) is on the inverse proportional function y=- 12/x,
∴n=- 12/6=-2, that is, B(6, -2)
And the straight line y = ∵A, b in kx+B.
∴ Equations: -2=6k+b
4=-3k+b
Solution: k=-2/3, b=2, that is, y=-2/3x+2.
(2) When the straight line AB intersects the X axis at point C, let point C (x, 0) be set.
If point c is substituted into the straight line y=-2/3x+2, then x=3.
S△AOC = S△AFC—S△AFO = 1/2cf×AF- 1/2of×AF = 1/2AF(CF-OF)= 1/2AF×OC = 1/2×4×3 = 6
That is, S△AOC=6.