⑵∠CBE=∠CAD,∠C=∠C∴⊿CBE∽⊿CAD

(3)aeb =∠ADB = 90 =∠bec, ∠ CBE = ∠ PBD ∴⊿ BDP ∽⊿ BEC makes BD/be = DP/EC;

From ⊿CAD∽⊿CBE, CA/CB = AD/BE is AB/AD = CB/BE = 2BD/BE = 2DP/EC.

That is ab/ad = 2dp/EC ∴ ab? CE=2DP？ advertisement