2[ 1+cosA]-[2(cosA)？ - 1]=7/2

Solution: cosA= 1/2.

A=60

( 1)

Then: sin(B+C)=2sinBcosC

Finishing: sinBcosC=cosBsinC

Solution: sin(B-C)=0, that is, b = c.

So: A = B = C = 60.

So △ABC is an equilateral triangle.

(2) According to the cosine theorem:

cosA=(b？ +c？ -a？ (2 BC)

Solution: b=2, c= 1 or b= 1, c=2.