X≥ 1 in the radical sign is x ≥ 1.
Defined by arcsin.
Then-1≤√ (x-1) ≤1gives 1≤x≤2.
So the domain is 1, 2.
2)2) What is the function y=log 1/3|x|(x belongs to r and x is not equal to 0)? * One third is the cardinal number, and x is the absolute value */
Let f(x)=log 1/3|x|
Because f(-x)=f(x)
So the function is even.
3) The straight line L passes through the fixed point (1, 3) and the triangle area enclosed by the straight line L and the two coordinate axes is equal to 6, then the equation of L is
Points A (1, 3), B (1, 0), C (0 0,3), D (0 0,0),
ABCD forms a rectangle with an area of 3.
The triangle surrounded by l has an area of 6,
Then l is parallel to BC with a slope of -3.
Then it is obvious that the L equation is 3x+y-6=0.
4) Given the complex number Z 1 = 1+2i and Z2 = 1-3i, the complex number of the * * * yoke of z 1+z2 is equal to
z 1+z2 = 1+2i+ 1-3i = 2-I
The complex number of soz65438 * * yoke+0+Z2 = 2+i.
5) Take out three numbers from the six numbers of 0, 1, 2, 3, 4 and 5, and multiply them once to get the number of different products as follows.
Multiply three numbers from 0 12345 from left to right.
0 and their product are both 0.
1*2*3=6
1*2*4=8
1*2*5= 10
1*3*4= 12
1*3*5= 15
1*4*5=20
2*3*4=24
2*3*5=30
2*4*5=40
3*4*5=60
So there are 1 1 * * in total.
6)arcsin[cos(3/4) batch] =/* Special self-parenthesis. . */
Arcsine [cos3π/4]
= Arcsine (-√2/2
=-π/4
7)sin42 degrees *sin72+cos42 degrees *cos72 degrees is equal to
cos(a-b)= cos(a)cos(b)+sin(a)sin(b)
therefore
Sin42 degrees *sin72+cos42 degrees *cos72 degrees.
=cos(72-42)
=cos30
=√3/2
8) If the area of triangle ABC is 64, and the median ratio of AB side and AC side is 12, then sinA is equal to.
S△ABC= 1/2AB*ACsinA
sinA=2S△ABC/AB*AC
=2*64/ 12^2=8/9
So Sina =8/9
9) Five people stand in a row, and the probability that Party A and Party B just stand on both sides is
There are two ways, a and b first, and then others. There are six methods, N=2*3*2= 12, so there are 12 methods standing on a * *. Then there are 120 ways to take pictures of five people, so the probability is one in ten.
10) The linear equation with a distance of (root number 2)/2 and a slope of 1 is
The topic can be abstracted as a circle with a radius of 2/2 below the root sign tangent to two straight lines with a slope other than 1.
Let the linear equation be y = x+b.
Simultaneous equation y=x+b ①
x？ +Y？ = (2/2 under the root sign)? ②
Substitute ① into ②
Solve 2X? +2bX+b？ - 1/2=0
Triangle =0
The solution is b= plus or minus 1.
So y=x+ 1 or y=x- 1.