Current location - Training Enrollment Network - Mathematics courses - Seek the grand finale of eighth grade mathematics. Moving point problem of geometry. The answer is more detailed. You can answer directly or send an email.
Seek the grand finale of eighth grade mathematics. Moving point problem of geometry. The answer is more detailed. You can answer directly or send an email.
1

tanB=AC/BC=3√3/9=√3/3

∠B=30

∠ China =∠QRC=∠B=30.

2

QR is perpendicular bisector of CP.

Q is the midpoint of communication.

x=AC/2=3√3/2

three

∠BRE= 180 -30 -30 = 120

∠REB = 180- 120-30 = 30 =∠B

y=2BRcos30

BR=9-CR

CR=CQtan30

CQ=3√3-x

y=2√3/2(9-(3√3-x)√3/3)

y=9√3/2+x

Domain (0,3 √ 3/2)