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Eight mathematical application problems
1) solution: it is required to be completed in x days.

1/(2x

4)

1/(2x- 16)= 1/24

12(x-8)

12(x

2)=(x

2)(x-8)

x^2

2x-8x- 16- 12x

96- 12x-24=0

x^2-30x

56=0

X 1=2 (omitted), x2=28.

Party A and Party B can finish it within the specified time.

(2) A alone needs 2×28.

4=60 days, and B alone is 2×28- 16=40 days.

( 1-5/6)÷(28-24×5/6)

= 1/6÷8= 1/48

∫ 1/60 & lt; 1/48< 1/40

Only by transferring Group A can it be completed on time.