Mathematical formula 1. X number of shares per share = total number of shares/number of shares = 2. 1 multiple x multiple = total multiple1multiple = total multiple/multiple = 1 multiple 3. Speed. Price/unit price = total quantity/quantity = unit price 5. Work efficiency × working time = total work ÷ work efficiency = working time ÷ total working time = work efficiency 6. Appendix+Appendix = sum-one addend = another addend 7. Minus-Minus = Difference Minus-Difference Factor 9. Divider ÷ Divider = quotient dividend ÷ quotient = divisor quotient × divisor = calculation formula of primary school mathematical graphs 1. Square c perimeter s area a side length perimeter = side length x ×4 C=4a area = side length x side length s = a x a 2. Cube v: volume a: side length. Volume = side length × side length × side length V=a×a×a 3. Rectangular c perimeter s area a side length perimeter = (length+width) × 2 C = 2 (a+b) area = length × width S=ab 4. Cuboid v: volume s: area a: length b: width h: height (65438 ×2 S=2(ab+ah+bh) (2) volume = length× width× height V=abh 5. Triangle s area a base h height area = base x height ÷2 s=ah÷2 triangle height = area x 2 base triangle base = area x 2 height 6. Parallelogram s area a base h height area = base x height s=ah 7. × height ÷2 s=(a+b)× h÷2 8. Circular s area c perimeter ∏ d= diameter r= radius (1) perimeter = diameter x ∏ = 2 x ∏ radius c = ∏ d = 2. Bottom area r: bottom radius c: bottom perimeter (1) lateral area = bottom perimeter x height (2) surface area = lateral area+bottom area x 2 (3) volume = bottom area x height (4) volume = lateral area ÷ 2 x radius 10. Cone v: volume h: height s. bottom area r: bottom radius volume = bottom area × height ÷3 Total number ÷ Total number = formula (sum+difference) ÷ 2 = large number (sum-difference) ÷ 2 = sum of decimals and multiple problems ÷ (multiple-/kloc-0 = decimal × multiple = large number (or decimal+difference = large number) Tree planting problem 1. The problem of planting trees on the closed line can be divided into the following three situations: (1) If trees are planted at both ends of the closed line, then: number of plants = number of segments+1 = total length ÷ plant spacing-1 total length = plant spacing × (number of plants-1) plant spacing. If you want to plant trees at one end of the unclosed line, at the other end. Then: number of plants = number of nodes = total length ÷ plant spacing = plant spacing × number of plants = total length ÷ plant number (3). If trees are not planted at both ends of the closed line, then: number of plants = number of segments-1 = total length ÷ plant spacing-1 total length = plant spacing × (number of plants+1) plant spacing = total length ÷ (number of plants+1) 2. The quantitative relationship of closed-line tree planting problem is as follows: the difference between two distributions = the number of shares participating in distribution (big profit-small profit); the difference between two distributions = the number of shares participating in distribution (big loss-small loss); the difference between two distributions = the number of shares participating in distribution meets the problem; Meeting distance = speed × meeting time = meeting distance; The sum of speed and speed = meeting distance; Meeting time; Catch up with the problem; Distance = catch up with time; Distance; Speed difference = catching distance; Catch up with time; Downstream velocity = degree-water velocity = (downstream velocity+countercurrent velocity) ÷2 Water velocity = (downstream velocity-countercurrent velocity) ÷2 Concentration problem Solute weight+solvent weight = solution weight ÷ solution weight × 100% = concentrated solution weight × concentration = solute weight ÷ concentration = × 100% increase or decrease = principal× increase or decrease percentage discount = actual selling price ÷ original selling price× 1 00% (discount <1) interest = principal× interest rate× time after tax interest = principal× interest rate× time × (1-)