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Looking for rules in mathematics in grade three
135 three digital periods

32÷3= 10……2

That is, the 32nd number is 10 cycle of 135, and there are 2 numbers left.

The second number in 135 is 3, so the 32nd number is 3.

Law: the nth number is divided by 3,

The remainder is 1, which is the first number of 135.

The remainder is 2, which is the second number 3 of 135;

The remainder is 0, which is the third number 5 of 135.