Method 1: If the cage is full of chickens, there are 35× 2 = 70 feet, and there are 94-70 = 24 extra feet. A rabbit has two more feet than a chicken, which means there are 24 ÷ 2 = 12 rabbits. So there are 23 chickens and 12 rabbits in the cage. Method 2: Solution: There are (35-x) chickens with X rabbits. Chickens and rabbits have 94 feet. Namely: 4x+2 (35-x) = 942x+70 = 94x =12. 35- 12 = 23 (chickens) A: rabbits 12, 23 chickens. Method 3: If the chicken raises one foot and the rabbit raises two feet, there are 94 ÷ 2 = 47 feet. At this time, every chicken has one foot and every rabbit has two feet. As long as there is a rabbit in the cage, the total number of feet is more than the total number of heads 1. At this time, the difference between the total number of feet and the total number of heads is 47-35 = 12, which is the number of rabbits, so there are 35- 12 = 23 chickens. Method 4: Enumeration I recommend the first method. Listed as: rabbit: [94-(35× 2)] ⊙ (4-2) = [94-70] ⊙ 2 = 24 ÷ 2 = 12 (only) chicken: 35-12 = Here, my hands are sore!