( 1)3-4×(-3.5)=0

(2) If a and -2 are reciprocal, then a2-2a = 1.

(3)-( )2=-

(4)-(- 1)3×(-0.2)3=0.008.

(5)0.25× 1 +0.75÷ = .

(6)(-4)+(-7)-(-2 1)=-4-7+2 1.

(7)|- 1.3|+0÷(5.7×|- |+ )= 1.3.

(8) (A-2) 2+| B-4 | = 0, then A = 2 and B = 4.

fill (up) a vacancy

( 1)-32×5-(-4)2×2=_________.

(2)(- 1)4-5×(- )3=________.

(3)-(-3)2-33=_________.

(4)-32÷(-3)2+(-2)4÷(-24)=_________.

(5)|(- 1)7-(-2)3|=__________.

(6) If | A-3 |+| B+| = 0, then BA = _ _ _ _ _ _ _

(7) use ">" or "

①-32____________ (-2)2; ②- ____________-|- |;

③(- 1)53____________? (-2)37;

calculate

[-|98|+76+(-87)]*23[56+(-75)-(7)]-(8+4+3)

5+2 1*8/2-6-59

68/2 1-8- 1 1*8+6 1

-2/9-7/9-56

4.6-(-3/4+ 1.6-4-3/4)

1/2+3+5/6-7/ 12

[2/3-4- 1/4*(-0.4)]/ 1/3+2

22+(-4)+(-2)+4*3

-2*8-8* 1/2+8/ 1/8

(2/3+ 1/2)/(- 1/ 12)*(- 12)

(-28)/(-6+4)+(- 1)

2/(-2)+0/7-(-8)*(-2)

( 1/4-5/6+ 1/3+2/3)/ 1/2

18-6/(-3)*(-2)

(5+3/8*8/30/(-2)-3

(-84)/2*(-3)/(-6)

1/2*(-4/ 15)/2/3

-3x+2y-5x-7y

Is it all?