So AB=AD=3 CD=BC=5, so the perimeter of the quadrilateral ABCD: ab+ad+CD+BC = 3+3+5+5 =16cm.

5. Solution: According to the question, BC=AE+BE= 5 under the radical sign? -3 under the root symbol? = 4 cm

The circumference of △ABE is AB+BE+AE=AB+BC=3+4=7cm.

I hope I can help you.