Let the equation be y = kx+b, and the distance from the center of the circle to the straight line under the root sign d = | b |12+k2 = 5 2-4 2; A straight line passes through (-3,-1.5), the coordinates are substituted into the equation and solved simultaneously ... and the distance from the abscissa of that point to the center of the circle is not one, so there is no straight line perpendicular to the X axis. The equation is the answer you solved above.