Well, the first question can obviously enclose two kinds of cylinders, one with a base perimeter of 3 and the other with a base perimeter of 2. The volumes of the two cylinders are respectively (the following is just a formula, LZ can be calculated by itself).

π (3/2π) 2× 2 and π (1/π) 2× 3. The result is that a cylinder with a base of 3 and a circumference of 2 has the largest volume, and the result is 9 divided by 2π.

The second question is a bit hateful, it is deceiving people in another way ~ ~ ~

The ratio of the radius of the cone bottom to the radius of the cylinder is 4: 1, that is, the ratio of their bottom areas is s cone /S cylinder = 16: 1. In this case, make their volumes equal, that is,

(1/3)S cone× h cone = s cylinder× h cylinder.

Results: H cone /h column = 3 (S column /S cone) = 3 (116) = 3/16.

This is like this ~ ~ ~

Good night, LZ…… ... ...