g=f2(x)+2af(x)+3= z^2+2a*z+3

=(z+a)^2+3-a^2

Because h(a) is the minimum value, that is, the minimum value of |z+a|.

So a & gt=-5/3, h (a) = (1/3+a) 2+3-a 2.

A< is at -5/3, and h (a) = (3+a) 2+3-a 2.

Because m>n>3 a belongs to [n m], H (a) = (1/3+A) 2+3-A2 = (2/3) A+28/9.

(2/3) n+28/9 = n 2 according to the meaning of the question.

It is known that the solution n 1 n2 has 1 plus 1 minus, which corresponds to the value of n and the value of m due to m >. N> So such an m n does not exist.