Effective time = S/(V+A)
Possibly advanced =S/V- S/(V+A)
2。 Original formula = (2-x/x-1) ÷ {[(x+1) (x-1)-3]/x-1}
=(2-x)/(x? 0? 5-4)
=2+X
Is it specific enough?
3. The original formula =1/(x-1)-1/(x? 0? 5-x)
=(x- 1)/(x- 1)x
= 1/x
Bring x=2 into the original equation.
Original formula = 1/2
Pick me. Pick me.
I entered it in detail.