Effective time = S/(V+A)

Possibly advanced =S/V- S/(V+A)

2。 Original formula = (2-x/x-1) ÷ {[(x+1) (x-1)-3]/x-1}

=(2-x)/(x？ 0? 5-4)

=2+X

Is it specific enough?

3. The original formula =1/(x-1)-1/(x? 0? 5-x)

=(x- 1)/(x- 1)x

= 1/x

Bring x=2 into the original equation.

Original formula = 1/2

Pick me. Pick me.

I entered it in detail.