PD=CQ, so 24-t=3tt=6 isosceles trapezoid: because BC-AD=2, the lower base of the isosceles triangle is 4 longer than the upper base, that is, PD+4=CQ, so 24-t+4=3tt=7.

The midpoint g of 15 AB is connected with eg.

∵ The quadrilateral ABCD is the square ∴∠ B = 90 ∴∠ BAE+∠ BEA = 90 because AE ∴∴ EF ∴∠ BEA+∠ FEC = 90.

Because CF is the bisector of the outer corner of ∠DCB, DFC = 45, ECF = 90+45 = 135, AE=EF.