∵EF⊥CE
∴∠AEF +∠CED =90
∠∠AEF+∠AFE = 90
∴∠AFE =∠CED
∠∠A =∠D = 90，EF=EC
∴△AFE≌△DEC
(2)
Let AE = X.
∫△AFE?△ December
∴AF=DE= 1,CD=AE=x
The circumference of a rectangle is 12cm.
∴AD+CD=6
∴ 1+x+x=6
∴2x=5
∴x=2.5
∴AE=2.5