The best of five games means that the first three victories are enough, and there is no need to forget the fourth game.

I wish you success in your studies!

Please do the math yourself!

A good teacher can only give directions!

After all, others can't replace you in the exam!

I'm glad to help others!

o(≧v≦)o~~

Solution: The number of games won by Team A may be: 0, 1, 2, 3.

P (= 0) = (1-p) 3 needs no explanation.

P( = 1)=3p×( 1-p)^3

I won once in the first three times and lost the fourth time.

P( =2)=6p^2×( 1-p)^3

I won twice in the first four times and lost the fifth time.

p(=3)=6p^3×( 1-p)^2+3p^3×( 1-p)+p^3

Win p 3 the first three times

The first three games 1 lose, and the fourth game 3p3x (1-p).

Win the fifth game, that is to say, win 6p3x (1-p) 2 in the first two games.

Remember the formula!

I believe you can solve the rest yourself!

Learn to think independently!

If you do not understand, please ask again!