There are three numbers a, b and c, and it is known that a+b= 1①, b+c=2②, and a+c=3③. Looking for A+B+C b+C.
Then the analysis shows that ①+②+③=2a+2b+2c= 1+2+3=6, then a+b+c=2.
Similarly, this question is analyzed as 2014× s =1+2+3 ...+2014 (s is the sum of these 20 15 numbers).
Get S= 1007.5.
Lying in the trough Is the topic all right? I thought it was an integer.