Then the number of people allocated to each venue can only be (1, 1, 3) and (1, 2,2).
Consider the combination of (1, 1, 3).
There are c (5, 1) ways to choose 1 person from 5 people first.
There are C (4, 1) ways to choose 1 from the remaining four people.
Finally, there is the method of C (3,3) to select 3 people from the remaining 3 people.
Therefore, for the combination of (1, 1, 3),
There are c (5, 1) * c (4,1) * c (3,3) = 20 methods;
Similarly, for the combination of (1, 2,2),
There are C(5,1) * c (4,2) * c (2,2) = 30 methods.
Because,
(1, 1, 3) combination If the arrangement order is considered,
There are three possibilities (1, 1, 3) (1, 3, 1) (3,1);
(1, 2, 2) combination If the arrangement order is considered,
There are three possibilities (1, 2,2) (2, 1, 2) (2,2,1);
So,
The final result is: 20 * 3+30 * 3 = 150 methods.