First, the answer to the question is clear. Because it is an even function, (-∞, 0) increases, so (0, +∞) decreases, and the function value of negative root number 2 is equal to the function value of root number 2. Combining with the drawing, we can know that if the function value of a- 1 of 2 is greater than the function value of negative root number 2, then there must be a-65438+ of 2. So the root number 2 must be on the right side of the-1 power of 2.

Secondly, as mentioned above, this power function is constant and cannot be less than the negative root sign 2, and because the function values of the positive and negative root signs 2 are equal, the domain should be evaluated with less than the root sign 2.