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Math problem: Xiao Ming and Xiao Lin are studying algebra M? When the values of +4m+8 are equal, two different conclusions are drawn.
m? +4m+8=(m+2)^2+4

(m+2) 2 represents the square of a number. When m= 1, 3, 5, 7, ... odd, (m+2) 2 is odd, odd plus an even or odd, so Xiao Ming's discovery is wrong.

When m=-2, (m+2) 2 = 0, (m+2) 2+4 = 0+4 = 4.

New discovery m? +4m+8 cannot be less than 4.

(m+2)^2>; =0,,(m+2)^2+4>; =(0+4)