(A/x)+(B/x+ 1)+(C/x+2)

= A(x+ 1)(x+2)/[x(x+ 1)(x+2)]

=[(A+B+C)x？ +(3A+2B+C)x+2A]/[x(x+ 1)(x+2)]

= x^2+2/x(x+ 1)(x+2)

So: (A+B+C)x? +(3A+2B+C)x+2A==x？ +2

= & gtA+B+C= 1 3A+2B+C=0 2A=2

= & gtA= 1 B=-3 C=3