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Solution to the problem of chickens and rabbits in the same cage in primary schools
The solution to the problem of chickens and rabbits in the same cage in primary schools is as follows:

Method 1:

(total number of feet-number of chicken feet × number of chickens) ÷ (number of rabbit feet-number of chicken feet) = number of rabbits.

Suppose rabbits are all chickens, and 1 has four feet. Imagine it as a chicken with two feet. Each rabbit is missing two feet, and * * * is missing one foot. There are several 2' s in A, which means several rabbits.

Total number-rabbit number = chicken number.

Method 2:

(number of rabbit feet × total feet-total feet) ÷ (number of rabbit feet-number of chicken feet) = number of chicken feet.

Suppose all chickens are rabbits, and 1 has two feet. If we think of it as a rabbit with four feet, then each chicken will have two more feet, counting one foot, and how many twos there are in A, that is, how many chickens.

Total number-number of chickens = number of rabbits.

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