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Su teaches printing plate elementary school mathematics 1-6 grade all formulas.
Su Jiaoban Elementary School Mathematics Formula 1-6

1, number of copies × number of copies = total number of copies/number of copies = total number of copies/number of copies = number of copies.

2. 1 multiple× multiple = multiple1multiple = multiple/multiple = 1 multiple

3. Speed × time = distance/speed = time/distance/time = speed.

4. Unit price × quantity = total price ÷ unit price = total quantity ÷ quantity = unit price

5. Work efficiency × working time = total workload.

Total amount of work ÷ work efficiency = working hours

Total workload ÷ working time = working efficiency

6. Appendix+Appendix = sum, and-one addend = another addend.

7. Minus-Minus = Minus-Minus = Minus+Minus = Minus

8. Factor × factor = product ÷ one factor = another factor.

9. Dividend = quotient dividend = divisor quotient × divisor = dividend

Calculation formula of mathematical graphics in primary schools

1, square c perimeter s area a side length perimeter = side length× 4c = 4a area = side length× side length s = a× a.

2. rectangle c perimeter s area a side length perimeter = (length+width) ×2 C=2(a+b) area = length × width S=ab.

3, triangle S area A base H height area = base × height ÷2 s=ah÷2

Height of triangle = area ×2÷ base of triangle = area ×2÷ height

4. parallelogram s area a base h height area = base x height s=ah

5. Trapezoidal S area A upper bottom B lower bottom H height area = (upper bottom+lower bottom) × height ÷2 s=(a+b)× h÷2.

6, circular S area C perimeter ∏ d= diameter r= radius

(1) perimeter = diameter ×∏=2×∏× radius C=∏d=2∏r (2) area = radius× radius× ∏.

7. Total number of copies = average total number of copies

Formula of sum and difference problem

(sum+difference) ÷ 2 = large number (sum-difference) ÷ 2 = decimal.

And folding problems.

Sum ÷ (multiple-1) = decimal × multiple = large number (or sum-decimal = large number)

Difference problem

Difference ÷ (multiple-1) = decimal × multiple = large number (or decimal+difference = large number)

Tree planting problem

1. The problem of planting trees on unclosed lines can be mainly divided into the following three situations:

(1) If trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes+1 = total length-1.

Total length = plant spacing × (number of plants-1) Plant spacing = total length ÷ (number of plants-1)

2 If you want to plant trees at one end of the unclosed line and not at the other end, then:

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants = total length ÷ number of plants

(3) If no trees are planted at both ends of the non-closed line, then:

Number of plants = number of nodes-1 = total length-1.

Total length = plant spacing × (number of plants+1) Plant spacing = total length ÷ (number of plants+1)

2. The quantitative relationship of planting trees on the closed line is as follows

Number of plants = number of segments = total length ÷ plant spacing

Total length = plant spacing × number of plants = total length ÷ number of plants

The question of profit and loss

(Profit+Loss) ÷ Difference between two distributions = number of shares participating in distribution.

(Big profit-small profit) ÷ Difference between two distributions = number of shares participating in distribution.

(big loss-small loss) ÷ The difference between two distributions = the number of shares participating in the distribution.

encounter a problem

Meeting distance = speed and x meeting time = meeting distance ÷ speed and

Speed Sum = Meeting Distance/Meeting Time

Catch up with the problem

Catch-up distance = speed difference × catch-up time = catch-up distance/speed difference

Speed difference = catching distance ÷ catching time

Tap water problem

Downstream velocity = still water velocity+flow velocity = still water velocity-flow velocity

Still water speed = (downstream speed+countercurrent speed) ÷2 Water flow speed = (downstream speed-countercurrent speed) ÷2

Concentration problem

Solute weight+solvent weight = solution weight/solution weight × 100% = concentration.

Solution weight × concentration = solute weight/solute concentration = solution weight.

Profit and discount problem

Profit = selling price-cost profit rate = profit/cost × 100% = (selling price/cost-1) × 100%.

Up and down amount = principal × up and down percentage

Discount = actual selling price ÷ original selling price× 1 00% (discount <1)

Interest = principal × interest rate × after-tax time interest = principal × interest rate × time × (1-20%)

Length unit conversion

1 km =1000m1m =1decimeter/decimeter =10cm1m =10cm/kloc-.

Area unit conversion

1 square kilometer = 100 hectare 1 hectare = 10000 square meter 1 square meter = 100 square decimeter.

1 dm2 = 100 cm2 1 cm2 = 100 mm2

Volume (volume) unit conversion

1 m3 = 1000 cubic decimeter 1 cubic decimeter = 1000 cubic centimeter 1 cubic decimeter = 1 liter.

1 cm3 = 1 ml 1 m3 = 1000 liter

Weight unit conversion

1t = 1000kg 1kg = 1000g 1kg = 1kg。