BC/sinA=AC/sinB=AB/sinC

3/ (root number 3/2) = AC/sinx = ab/sin (120-x)

So AC=2 3 sinx, AB=2 3 sin( 120-x).

Circumference f(x)=3+2 root number 3 sinx+2 root number 3 sin( 120-x)

=3+2 radical number 3 (sinx+ radical number 3/2cosx+ 1/2sinx)

=3+2 root number 3 (3/2sinx+ root number 3/2cosx)

=3+6 (root number 3/2sinx+ 1/2cosx)

= 3+6 sine (x+30)

Domain (0, 120)