OA=OA (common edge)

OD=OH (the distance from one point to both sides on the angular bisector is equal)

∴△OAD≌△OAH

∴∠AOD=∠AOH

∫∠ Dog =∠∠ Here comes the hoe again.

∴∠AOE=∠AOG

∠ 1=∠2 (known condition)

AO=AO

∴△AOE≌△AOG

∴OG=OE

2) Prove ∠ 1=∠2 in turn.

Known OG=OE

∠DOG=∠HOE (equal to vertex angle)

∠ODG=∠OHE=90

∴△ODG≌△EOH

∴OD=OD (the distance from one point on the angular bisector to both sides is equal)

It is proved that AO is the bisector of ∠GAE, ∠1= ∠ 2.