Therefore, a+c
Therefore |a+c|=-a-c, |a-b-c|=a-b-c, |b-a|=a-b, | b+a | =-b-a b-a.
Therefore | a+c |-a-b-c |+2 | b-a |-b+a | =-a-c-(a-b-c)+2 (a-b)-(b-a) = a.
|x+2|+|x-4|+|x+3|
(1) when x
Therefore |x+2|=-x-2, |x-4|=4-x, |x+3|=-x-3.
| x+2 |+| x-4 |+| x+3 | =-x-2+4-x-x-3 =-3x- 1
(2) When -3≤x≤-2, x+2, x-4≤0 and x+3≥0.
Therefore |x+2|=-x-2, |x-4|=4-x, |x+3|=x+3.
| x+2 |+| x-4 |+| x+3 | =-x-2+4-x+x+3 = 5-x
(3) When -2
Therefore |x+2|=x+2, |x-4|=4-x, |x+3|=-x-3.
| x+2 |+| x-4 |+| x+3 | = x+2+4-x+x+3 = x+9
(4) when x >; 4，x+2，x-4，x+3≥0。
Therefore |x+2|=x+2, |x-4|=x-4, |x+3|=x+3.
| x+2 |+| x-4 |+| x+3 | = x+2+x-4+x+3 = 3x+ 1
|x-2|+|x+5|
(1) when x
Therefore |x-2|=-x+2, |x+5|=-x-5.
|x-2|+|x+5|=2-x-x-5=-2x-3
(2) When -5≤x≤2, x-2≤0 and x+5≥0.
Therefore |x+2|=-x-2, |x+5|=x+5.
|x-2|+|x+5|=2-x+x+5=7
(3) When 2; 0
Therefore |x+2|=x+2, |x+5|=x+5.
|x-2|+|x+5|=x-2+x+5=2x+3
|x+3|-|x-2|
(1) when x
Therefore |x-2|=-x+2, |x+3|=-x-3.
| x-2 |+| x+3 | = 2-x-x-3 =-2x- 1
(2) When -3≤x≤2, x-2≤0 and x+3≥0.
Therefore |x-2|=-x+2, |x+3|=x+3.
|x-2|+|x+3|=2-x+x+3=5
(3) when x >; 2 o'clock, x-2, x+3 >; 0
Therefore |x-2|=x-2, |x+3|=x+3.
|x-2|+|x+3|=x-2+x+3=2x+ 1