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It is wrong to ask at least one girl to help you see the way of thinking if you want to choose four boys and two girls to participate in a community service in a class of basic mathematics.
Solution: Method 1: There are at least 1 girls in 4 people, including 1 girl, 3 men, 2 women and 2 men.
So the number of different options is C 12? C34+C22？ C24 = 2×4+ 1×6 = 14；
Option 2: Choose 4 men and 2 women * * * There are C46 ways to choose and C44 ways to choose 4 men.
So girls have at least 1, and the number of options is C46-C44 =15-1=14.