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Thinking questions in the second volume of sixth grade mathematics
1: In the quadrilateral ABCD, the angle B is 70, the angle C is 90, BC=CD, AB=AD, how many degrees do you find the angle A?

2. Each internal angle of a regular polygon is 20 larger than its adjacent complementary angle. What is the sum of the internal angles of this polygon? 3. If the minimum internal angle of a polygon is 120, the internal angle is slightly larger than it.

125, and then each internal angle is 5 larger than the previous internal angle, and the ratio of the maximum internal angle to the minimum internal angle is 4: 3. Find the number of sides of this polygon and the degree of the maximum internal angle.

1.

The angle b shown in the figure is equal to the angle d.

So angle a is

360-90-2*70= 130

2.

The complementary angle of the inner angle is (180-20)/4=40.

So the inner angle is 140.

It's Zheng Jiulang

The sum of internal angles is

140*9= 1260

3.

The maximum internal angle is 120/3*4= 160.

The number of sides is

( 160- 120)/5+ 1=9