Current location - Training Enrollment Network - Mathematics courses - Math in the third grade of primary school: for every 4 bottles of 20 yuan, give 1 bottle1bottle, and you need to buy 43 bottles. How much will it cost at least?
Math in the third grade of primary school: for every 4 bottles of 20 yuan, give 1 bottle1bottle, and you need to buy 43 bottles. How much will it cost at least?
Analysis: Since you buy a bottle with 10, it is actually a one-time purchase 1 1 bottle. You only need to know how many 1 1 bottles are in 43 bottles, and multiply them directly by1.

Solution:

Unit price 20÷4=5 (Yuan/bottle)

10 bottle price: 5× 10=50 yuan.

43÷( 10+ 1)= 3 remainder 10

The cost is 3×50+ 10×5=200 yuan.

A: At least 200 yuan.

Attachment: Note that 43 is 1 10 after removing three 18+00, which satisfies the condition that 10 is more than 10. The buyer must spend 200 yuan, but the number of bottles repurchased is 44, not 43, because the final 10 bottle needs to be given 65438+.