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Mathematical franchising problem
It should be rented like this: 24 large ships, small boats 1 ship.

Scheme 1: 148÷6=24 (only) ... 4 (person) 4÷4= 1 (only) 24×36+30=864+30=894 (yuan).

Scheme 2: 148÷4=37 (only) 37× 30 = 1 10 (yuan) 894 yuan <110 yuan.

Answer: 24 big ships, 1 small boats, are the cheapest way to charter a boat.

"Charter problem" is the content of Unit 1 "Four Calculations" published by Xinmin Education Publishing House. In the problem of chartering, the easiest thing to find is that it is the easiest to calculate if you only choose to rent a big boat or directly choose to rent a small boat, and I believe there is not much problem in the calculation process. According to the number of people and the current number of people per ship, how many ships are needed.

How to charter a boat;

It is a common mistake for students to choose only a big boat or a small boat to calculate the scheme and choose the best scheme after comparison. As we all know, in the process of chartering, taking the actual situation as an example, the per capita cost is cheaper than that of a boat. However, in the process of renting a big ship, there will be dissatisfaction and the purpose of choosing the best scheme will not be achieved, so the third scheme will be chosen at this time.

Secondly, it is not the best scheme to compare only big ships and small boats. Therefore, an important principle should be considered in the process of selecting two cases for calculation. If every boat is full, then it is necessary to choose the form of mixing big boats and small boats, which will save money and not empty seats.