14 * (square of 4) * 6/.14 * (8/12 = 850/,V = 3； when the height is 6; 3 So cylinder volume-cone volume =2/. 14*(R squared) * height = 120 cone volume = 3; 250 = x ǜ1(1) 200/2) * 6+3.14 * (4/.14 * (the square of 3)) 6 When the sixth question is incomplete, 7 is cut into the largest cylinder (. 2 square) *6 (2) Base diameter 6.84*0. 14*(6/2 square) 4144 * 2/15 (2)18; 3 3 2*3.5* 1; *3.6 (3) The cylinder volume is equal to 3; (3*3) 5 3. 14*(4/, when the height is 10, V=3, when the height is 8, v is definitely smaller than the ground (2), so comparing the size of (1)(2), the largest is the required area; 3* 120=80 2 let's assume that X x/