n≥2,an = Sn-S(n- 1)=(2an- 1/2)-(2a(n- 1)- 1/2)= 2an-2a(n- 1)
an=2a(n- 1)
an/a(n- 1)= 2
Therefore, the sequence {an} is a geometric series with the first term a 1= 1/2 and the common ratio of 2, and an =1/2 * 2 (n-1) = 2 (n ≥/kloc-)
bn=log? 2^n=n
Tn=b 1+b2+…+bn
= 1+2+…+n
=n(n+ 1)/2