Then the distance from p to the straight line x-y+3 =0.

S=|y^2/2-y+3|/√2

=|y^2-2y+6|/(2√2)

=|(y- 1)^2+5|/(2√2)

& gt=5/(2√2)

When y= 1 and x = 1 2/2 = 1/2, the distance s has a minimum value of 5√2/4.

All right!

Good luck!