1, connecting E and F. Because E and F are the midpoint of BC and BD respectively, EF is the center line of triangle BDC. Because AC=8, AD=2 and DC=6, the neutral line EF=3.

2. Because AD/AB=AB/AC and angle BAD= angle BAC, triangle ADB is similar to triangle ABC, and because E and F are the midpoint of BC and BD, AE is similar to AF. AE/AF=AC/AB, that is, AE: AF = 2: 1, AE=5, so AF=2.5.

3. AEF perimeter of triangle =AE+EF+AF=5+3+2.5= 10.5.