∴P (a) > p (b)、

So the answer is: >; ?

(2) B should choose the number 4.

The reasons are as follows: The possible results of pointing the pointer to the area number twice are as follows:

1 time

Second 1 2 3 1 (1, 1) (1, 2) (1, 3) 2 (2, 1) (2, 2)

(2,3) 3 (3,1) (3,2) (3,3) There are nine possible outcomes, and the possibility of each outcome is the same.

Among them, there are two possibilities for * * * with a sum of 3, that is, the probability p1= 29 with a sum of 3;

There are three possibilities for a * * * to have the sum of four numbers, that is, the probability of a * * having the sum of four numbers P2 = 13.

∵P2>P 1，

When b chooses the number 4, the probability of winning is greater than a.