∴CRB={x|-4≤x≤2}

∴a∩crb={x|-2<； x≤2}

Equation x? -4ax+3a？ =(x-3a)(x-a)

(1) If a=0, there is no solution, while C=? , in line with the meaning of the question.

(2) if a>0, C = {x | a<x & lt3a}

C is contained in A∩CRB, ∴a≥-2, 3a≤2, the solution is -2≤a≤2/3, and a>0 is simultaneous, and 0 is obtained.

(3) If

C is contained in A∩CRB, ∴3a≥-2, a≤2, and the solution is -2/3≤a≤2, a < 0, and get-2/3 ≤ a.