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Super problem of seventh grade mathematics
1, by

One third of x minus one third of y =0, one third of x = one third of y, y=3x, (

x? +XY-Y? )(X? +Y? )=3X? ÷ 10X? = three tenths

2. The original formula = 1+2-25÷ 1=-22.

3, multiply (X+3Y)÷(4X-Y)=3.

X+3Y=

12X-3Y gives 1 1x = 6y, and the value of x÷yis 165438+6/0.

4、X? + 10X+25=(x+5)? Is greater than 0, so X- 1 is less than 0, so x is less than 1.

5 、( 6X? - 12X+6)÷( 1-X)? =6÷( 1-X), (1-X) divisor x= 1/2, 1/3, 1/4,1/. .