Let y be the required maximum banana surplus and x be the required point (x meters), and the equation can be listed as follows:
1.Y=( 100-3X) - (50-X)
2.( 100-3X)& lt； =50
It's easy to find 3Y=50.
X=y= 16 and 2/3.
Because only one banana can be eaten when it is over one meter, X can be any number from 16 to 17, and y= 17.
To put it simply, the monkey first goes forward 16 and 1 m (16 can be followed by any real points), then puts down a banana every one meter and comes back. Eat bananas on the ground every other meter, and then take 50 bananas to 16 and 1. At this time, Yi * * walked 50 meters, ate 50 bananas, and there were 50 bananas left. The rest of the road is more than 33 meters, which means we still need to eat 33 meters, and finally there is 17.
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