There is a pile of black and white chess pieces, in which the number of sunspots is twice that of Bai Zi. If you take out four sunspots and three Bai Zi from this pile of chess pieces at the same time, how many times will Bai Zi have 1 and 18 sunspots?

After taking x times,

4X+ 18==( 1+3X)*2

X=8

I was adopted by my teacher.

The formula: (9- 1)/(3-2)=8 times (9- 1) means that there are 8 more spots than albinos, while (3-2) means that there are more albinos 1 each time, so every time you take them out, you will leave one more spot than albinos. You can also change Bai Zi to twice the number of sunspots, which is equivalent to taking four sunspots at a time, six in Bai Zi, two in Bai Zi 18. It is the same! Simply pull with equation