The two subtractions are: 2s-s = 2+22+23++2n+2 (n+1)-1+2+2n,
S=2^(n+ 1)- 1 .
2. let s =1+a+a 2+...+an n, then As = A+A 2+A 3+...+A N+A (n+ 1),
The two subtractions are as-s = [a+a 2+a 3+...+an+a (n+1)]-[1+a 2+...+an],
(a-1) s = a (n+1)-1,when a≠ 1, there are: s = a (n+1)-1
Third, if 0
= 1/( 1-a)-a^(n+ 1)/( 1-a)<; 1/( 1-a)。
Summary of Mathematics Final Exam 1
This Wednesday, we finally finished the exam. I feel good about myself in this final exam. No, I was so