And < b = < ade = 45.
Bader =∠CDE
Similarly ∠B=∠C
∴ △BAD∽△CDE
∴ AB/DC=BD/CE
That is AB*CE=BD*DC.
∴ 2(2-Y)=X(2√2-X)
Therefore, the resolution function is: Y=X? /2-√2X+2(0 & lt; X & lt2√2)
When △ADE is an isosceles triangle, △ bad △ CDE
∴BD=CE, then X = 2-Y.
Substituting it into the above analytical formula for classification, we can get AE=Y=. .........