The two sides OA and OC of the right-angled trapezoid ABCO are on the positive semi-axis of the coordinate axis BC//x, OA=OC=4, and the parabola with the straight line x= 1 as the symmetry axis passes through three points A, B and C. 。
(2) It is known that the analytical formula of the straight line L is y=x+m, and it intersects with the X axis at point G, taking point P on one side of the trapezoid ABCO.
(1) when m=0, as shown in figure 1, point p is the intersection of parabola symmetry axis and BC, and the area of triangle OPH is found;
(2) When m=-3, take the intersection point P as the vertical line between the X axis and the straight line L, and the vertical foot as points E and F. Is there such a point P, and the triangle with the vertices of P, E, F, E and F is an isosceles triangle? If it exists, find the coordinates of point P; If it doesn't exist,