But this topic also includes the flexible application of logarithmic operation.
Problem solving: First of all, you can see a> 1 from the diagram and get the value of f(0).
- 1 & lt; Log a (b) <; 0
Then 0
Left-1 to be deformed: it should be noted that the deformation of 1 should be flexible logarithmically, and 1 can usually be written as: log a (a).
Then-1 can be written as -loga (a) = loga (1/a).
According to a> 1, monotonically increasing, and then1/a.
A: A.