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Proof of monotonicity in higher mathematics?
f'(x)=e^x-e f(x)=e^x-ex

When x> is at 1, f' (x) > e1-e = 0-e = 0, so f(x) is in x >; 1 interval monotonically increases.

And f( 1)=e-e =0, so when x >；; At 1, f (x) >: F( 1)=0 is E X >；; Ex-husband; Ex-wife; Ex-boyfriend; Ex-girlfriend

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