Here we need to know that the minute hand turns 6 per minute. The hour hand turns 0.5 per minute? Then turn it into a pursuit problem.

If the hour hand is between 7 o'clock and 8 o'clock, when will the hour hand and minute hand coincide?

At 7 o'clock sharp, the angle between the hour hand and the minute hand is 2 10? The pursuit result is coincidence, and we can regard it as the pursuit distance of 2 10, according to

Pursuit distance = speed difference x pursuit time (in this question, the pursuit time is equal, set to x? )

2 10=(6-0.5)* ×

X=420/ 1 1

So 7: 00 420/ 1 1 coincides.

I hope I can help you!