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mathmatics Ok, help me calculate.
At least 176 can be played, and the scheme is as follows:

2. 13/0.96 & gt; Two layers can be placed in this direction;

On the remaining surfaces, 5.7/0.22 >: 25, 5.7/.061>; 9;

Along the direction of 2. 18, first lay a layer with a width of 0.6 1, and then put 25 pieces;

Then vertically press the height 0.22, (2.18-0.61)/0.22 > 7. You can put 7 floors or 9 floors.

At this time * * * put 25+7*9=88, and the second floor *** 176.

note:

1, along the direction of 2. 18, when the second or third floor is tiled with the width of 0.6 1, the actual number of tiles is as follows:

2*25+4*9=86,

3*25+9=84, not as much as the above scheme.

2. There may be another optimal placement scheme for the remaining space of 5.7 * (2.13-0.96) * 2.18 after placing one floor according to the above scheme.

3. The guiding ideology of the above idea is: firstly, match the shortest side (2. 13) of the large cabinet according to the largest side (0.96) of the box to be placed, and then match the remaining shorter side (2. 18) with the remaining longer side (0.6 1). Whether this idea is correct remains to be discussed, but at least a relatively optimal solution can be obtained.