PD AB,PE AC
∴∠ABP=∠DPB,∠ACP=∠EPC
∫BP and CP are equally divided ∠ABC and ∠ACB respectively.
∴∠ABP=∠DBP,∠ACP=∠PCB
∴∠DPB=∠DBP,∠EPC=∠PCB
∴BD=PD,PE=EC
∴c△pde=pd+pe+de=bd+de+ec=bc=5cm