Look at the picture. S 1 is a square triangle with side length of 1, hypotenuse length of 1 and angles of 30 and 60.

Square area = 1* 1= 1.

Triangle area =1/2 *1sin30 * √ 3 *1sin30 = √ 3/8 (the opposite side of 60 is three times the root with a side length of 30).

Get S 1= 1+√3 /8.

(2) The side length of the first square is N 1= 1.

The side length of the second square is the opposite side of the first square △ 60, that is, N2 = n 1sin30 * √ 3 = √ 3/2.

Inference: nn = (√ 3/2) (n- 1)

sn=nn^2+nnsin30 * 1/2 * nns in 60 =(√3 /8+ 1)*(√3/2)^2(n- 1)